How do you find the equation of a circle with center?

The equation of circle with (h,k) center and r radius is given by: (x-h) 2 + (y-k) 2 = r 2. Thus, if we know the coordinates of the center of the circle and its radius as well, we can easily find its equation. Example: Say point (1,2) is the center of the circle and radius is equal to 4

What is the formula to find the radius of a circle?

Therefore, the radius of a circle is CP. By using distance formula, (x-h) 2 + (y-k) 2 = CP 2. Let radius be ‘a’. Therefore, the equation of the circle with centre (h, k) and the radius ‘ a’ is, (x-h) 2 +(y-k) 2 = a 2. which is called the standard form for the equation of a circle. Equation of a Circle in General Form

How do you find the tangent of a circle?

Find the equation of a circle which touches both the axes and the line 3x−4y+8=0 and lies in the third quadrant. Let ‘a’ be the radius of the circle. Given that the line 3x−4y+8=0 touches the circle. ∴3x−4y+8=0 is tangent to the circle.

What is the center of a circle called?

was iorn and that er and COORDINATE GEOMETRY OF THE CIRCLE EQuation of a Circle, Centre (0, 0) and Radius r A circle is a set of points (a locus) which are equidistant from a fixed point called the ‘centre’. The distance from the centre to any point on the circle is called the ‘radius’.

What is the radius of the circle perpendicular to 3x-4y+1?

Now you know the radius of the circle, it is 1. The line perpendicular to 3x-4y+1=0 and which passes through (2, 3) is 4x+3y-17=0. The intersection of the two lines is the tangent point of the line and circle at (13/5, 11/5).

How do you find the distance between a circle and a line?

When you say the circle touches that line, it means the line is tangent to it, thus, the distance between the center C and the line [math]5x + 12y – 19 = 0 [/math] is exactly the radius. Something like that. Where a, b, and c are the coefficients of the line (ax + by + c = 0), and x and y are the coordinates of the point.