How many four digits numbers can be formed with the digits 3 4 5 6 Find the sum of all the numbers thus formed?

In the 24 numbers formed each of the 4 digits will occur a total of 6 times in each position. Therefore, the total sum of the digits in each position is 6*(3+4+5+6) = 108.

What is the sum of all the 4 digit numbers that can be formed using all of the digits?

There are total 4^4 = 256 combinations. Each digit comes in every place 4^3 = 64 times. Sum of all digits in each place = 64 ( 1+2+3+4 ) = 640.

How do you find the sum of digits in a number in C?

To get sum of each digits by c program, use the following algorithm:

1. Step 1: Get number by user.
2. Step 2: Get the modulus/remainder of the number.
3. Step 3: sum the remainder of the number.
4. Step 4: Divide the number by 10.
5. Step 5: Repeat the step 2 while number is greater than 0.

How many 4 digit numbers can be formed using the digits 2 4 6 8 with repetition and without repetition of digits is allowed?

∴ Total numbers = 4 + 12 + 24 + 24 = 64 numbers.

What is the sum of all 4 digit numbers formed using the digits 2 3 4 and 5 without repetition *?

93, 324
The sum of all the 4-digit numbers formed using the digits 2, 3, 4, and 5 (without repetition) is 93, 324.

What is the sum of all of the four digit integers that can be created with the digits 1 2 3 and 4?

The smallest number that can be created from 1, 2, 3, and 4 is 1111, and the largest number possible is 4444. Then the average is (1111 + 4444)/2. So sum = 5555/2 * 256 = 711,040.

How do you find the sum of all digits of numbers?

Sum of digits algorithm

1. Step 1: Get number by user.
2. Step 2: Get the modulus/remainder of the number.
3. Step 3: sum the remainder of the number.
4. Step 4: Divide the number by 10.
5. Step 5: Repeat the step 2 while number is greater than 0.

How do you find the sum of the 120 valid 4-digit numbers?

So we calculate the sum of the 120 valid 4 digit numbers by first looking at the sum of the digits in the thousands place. This sum is The 1000 comes from looking at the sum of the digits in the thousands’ place. The solution you provided factored this result as 1000 ∗ 24 ∗ ( 1 + 2 + 3 + 4 + 5).

What is the sum of all four digit numbers formed?

Now, sum of all four digit numbers formed = Sum of all numbers − Sum of numbers with 0 in the first place. Hence, the answer = 66660−2220= 64440. Was this answer helpful?

How many 4-digit numbers are there in 2/4 units?

When we take all distinct 4 digit numbers using there digits, it is only obvious that 4 will be in units place in 2/4 of these, while 2 or 3 will be in units place in 1/4 (each) of these. Clearly, there are total 4!/2! = 12 such numbers.

How many total numbers can be formed using 5 digits?

One answer: Total numbers formed using those 5 digits is 5P4. i.e. 120 numbers. Since all digits will equally occupy the unit’s place, therefore 1 will occur 24 times in unit’s place. Similarly 2 will occur 24 times in unit’s place. So on and so forth. Therefore sum of all digits in unit’s place will be equal to 24 x (1+2+3+4+5)=24 x 15.