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What is the range of a COS x B sin x?

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What is the range of a COS x B sin x?

The range must be [- root (a^2 +b^2), +root (a^2 +b^2)].

What is the range of sin x and cos x?

Note that the domain of the function y=sin(x) ) is all real numbers (sine is defined for any angle measure), the range is −1≤y≤1 . The graph of the cosine function looks like this: The domain of the function y=cos(x) is all real numbers (cosine is defined for any angle measure), the range is −1≤y≤1 .

What is the maximum value of a COS x B sin x?

But, maximum value of cos(α-x) is 1.

What is the range of cos sin x?

cos X ranges from -1 to 1. We need max value of sin(cos(X)). Sin is odd function and is negative from -π to 0.

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What is the range of Cos X?

-1 to 1
So, the domain of cos(x) is all real numbers. Also, the value of cos(x), depending on the point on the circle, can go to a maximum of 1 at x = 0 degrees and a minimum of -1 at x = 180 degrees. So, the range of cos(x) is from -1 to 1.

What is the range of 3sinx 4cosx?

Hence the range is [−10, 0].

How do you find the range of sin x cos x?

find range y =|sin x|+|cos x|

  1. Domain : Domain of the function f(x) will be the intersection of domains of sinx and cosx.
  2. Therefore, the domain is (-∞,+∞).
  3. Range : Range of any continuous funtion lies inbetween the minimum and maximum value of that function.
  4. Thus the range of the function f(x) is [-√2,√2].
  5. thankyou.

How do you find the maximum value of sin theta cos theta?

The maximum value of sin θ + cos θ in [θ , π/2] is. Maximum value will be obtained when θ + π/4 = /2 and the maximum value will be √2.

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What is the fundamental period of sin x?

2π
For example, both sin x and cos x have fundamental period 2π, whereas tan x has fundamental period π.

What is the range of sin sinx?

the range of sin(sinx) is -pi/2 , pi/2.

What is the range of sin?

In the sine function, the domain is all real numbers and the range is -1 to 1.

What is the range of the desired function f(x)?

Therefore the range of the desired function f (x) is from – ( a 2 + b 2) to ( a 2 + b 2) . The way I’ve explained, don’t need any sort of assumptions, like the one you’ve mentioned in the comment. Hope that helps. The range must be [- root (a^2 +b^2), +root (a^2 +b^2)].

What is the domain of f(x) = sinx+cosx?

Let f (x)=sinx+cosx. Domain : Domain of the function f (x) will be the intersection of domains of sinx and cosx. As the domain of sinx as well as cosx is (-∞,∞), thus the domain of the funtion f (x) will the the intersection of the two domains which comes out to be (-∞,∞) that is, that x can take any real value ranging from -∞ to +∞.

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How do you find the range of a function with √2?

To find Range of function first convert it into either sin or cosine. do multiply and divide with √2 ,assume 1/√2 as cos y and sin y respectively. hence, -√2<= sin (x+y)<=√2….range of given function. Domains starting from $1 with free privacy protection.

What is the intersection of SiNx and cosx?

Domain : Domain of the function f(x) will be the intersection of domains of sinx and cosx. As the domain of sinx as well as cosx is (-∞,∞), thus the domain of the funtion f(x) will the the intersection of the two domains which comes out to be…